Exercise (2.2.20.a): Let $G$ be an abelian group, and $a,b \in G$. Let $m,n$ be the orders of the groups generated by $\langle a \rangle$ and $\langle b \rangle$. What can you say about the order of $\langle ab \rangle$?
We consider the elements generated by $\langle ab \rangle$:
- 1 (identity).
- $ab$.
- $(ab)^2 = abab$. Since the group is commutative, we can reorder like this: $aabb = a^2b^2$.
- $(ab)^k = a^kb^k$, more generally.
Therefore, once we reach either $(ab)^m$ or $(ab)^n$, whichever's the smallest of $m$ and $n$, we will be left with the rest of the cyclic group generated by $a$ or $b$. So, we can conclude that the order of $\langle ab \rangle$ is in fact the order of $a$ or $b$.
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